1. Find the moles of HCl:

* Molar mass of HCl: 1.01 g/mol (H) + 35.45 g/mol (Cl) = 36.46 g/mol

* Moles of HCl: (85.6 g HCl) / (36.46 g/mol HCl) = 2.35 mol HCl

2. Calculate the molarity:

* Molarity (M): Moles of solute / Liters of solution

* Molarity: (2.35 mol HCl) / (0.385 L solution) = 6.10 M

Therefore, the molarity of the HCl solution is 6.10 M.