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  • Calculating Moles of Ammonium Ions in Ammonium Carbonate: A Step-by-Step Guide
    Here's how to solve this problem:

    1. Determine the Formula of Ammonium Carbonate

    Ammonium carbonate has the formula (NH₄)₂CO₃. This means it contains:

    * Two ammonium ions (NH₄⁺)

    * One carbonate ion (CO₃²⁻)

    2. Find the Molar Mass of Ammonium Carbonate

    * N: 14.01 g/mol * 2 = 28.02 g/mol

    * H: 1.01 g/mol * 8 = 8.08 g/mol

    * C: 12.01 g/mol * 1 = 12.01 g/mol

    * O: 16.00 g/mol * 3 = 48.00 g/mol

    Total molar mass of (NH₄)₂CO₃ = 28.02 + 8.08 + 12.01 + 48.00 = 96.11 g/mol

    3. Calculate the Moles of Ammonium Carbonate

    Assume you have 6.965 g of ammonium carbonate:

    Moles = mass / molar mass

    Moles = 6.965 g / 96.11 g/mol = 0.0725 moles of (NH₄)₂CO₃

    4. Determine the Moles of Ammonium Ions

    Since each mole of ammonium carbonate contains two moles of ammonium ions:

    Moles of NH₄⁺ = 0.0725 moles (NH₄)₂CO₃ * 2 moles NH₄⁺ / 1 mole (NH₄)₂CO₃ = 0.145 moles of NH₄⁺

    Therefore, there are 0.145 moles of ammonium ions in 6.965 grams of ammonium carbonate.

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