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  • Lead Acetate and Copper Sulfate Reaction: Products & Explanation
    The reaction between lead acetate (Pb(CH₃COO)₂) and copper sulfate (CuSO₄) is a double displacement reaction. Here's what happens:

    * Reactants:

    * Lead acetate (Pb(CH₃COO)₂) - a colorless to white solid

    * Copper sulfate (CuSO₄) - a blue solid

    * Products:

    * Lead sulfate (PbSO₄) - a white precipitate (insoluble in water)

    * Copper acetate (Cu(CH₃COO)₂) - a blue-green solution (soluble in water)

    The balanced chemical equation is:

    Pb(CH₃COO)₂ (aq) + CuSO₄ (aq) → PbSO₄ (s) + Cu(CH₃COO)₂ (aq)

    Here's a breakdown of the reaction:

    * The lead ions (Pb²⁺) from lead acetate react with the sulfate ions (SO₄²⁻) from copper sulfate.

    * Lead sulfate (PbSO₄) is formed, which is insoluble in water and precipitates out as a white solid.

    * The copper ions (Cu²⁺) from copper sulfate react with the acetate ions (CH₃COO⁻) from lead acetate.

    * Copper acetate (Cu(CH₃COO)₂) is formed, which is soluble in water and remains in solution, giving the solution a blue-green color.

    In summary:

    When you mix a solution of lead acetate with a solution of copper sulfate, you'll observe the formation of a white precipitate (lead sulfate) and the solution will turn blue-green due to the presence of copper acetate.

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