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  • Calculating Sulfuric Acid Required for Ammonium Hydroxide Reaction
    Here's how to solve this problem:

    1. Balanced Chemical Equation

    The reaction between sulfuric acid (H₂SO₄) and ammonium hydroxide (NH₄OH) is:

    H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O

    2. Mole Ratio

    The balanced equation shows that 1 mole of sulfuric acid reacts with 2 moles of ammonium hydroxide.

    3. Calculate Moles of Sulfuric Acid

    Since we have 8 moles of ammonium hydroxide, we need half that amount of sulfuric acid:

    8 mol NH₄OH * (1 mol H₂SO₄ / 2 mol NH₄OH) = 4 mol H₂SO₄

    4. Convert Moles to Grams

    The molar mass of sulfuric acid (H₂SO₄) is approximately 98 g/mol.

    4 mol H₂SO₄ * (98 g/mol) = 392 g H₂SO₄

    Therefore, you need 392 grams of sulfuric acid to react with 8 moles of ammonium hydroxide.

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