1. Balanced Chemical Equation

The reaction between sulfuric acid (H₂SO₄) and sodium chloride (NaCl) produces hydrochloric acid (HCl) and sodium sulfate (Na₂SO₄):

H₂SO₄ + 2NaCl → 2HCl + Na₂SO₄

2. Determine the Limiting Reactant

* H₂SO₄: You have 2.00 mol of H₂SO₄.

* NaCl: Convert grams of NaCl to moles using its molar mass (58.44 g/mol):

150 g NaCl * (1 mol NaCl / 58.44 g NaCl) = 2.57 mol NaCl

To find the limiting reactant, compare the mole ratio of reactants to the balanced equation:

* H₂SO₄: 2.00 mol H₂SO₄ / 1 = 2.00

* NaCl: 2.57 mol NaCl / 2 = 1.29

The smaller value (1.29) corresponds to NaCl. This means NaCl is the limiting reactant because it will be completely consumed before all of the H₂SO₄ is used up.

3. Calculate the Moles of HCl Produced

Using the stoichiometry from the balanced equation, we can find the moles of HCl produced:

2.57 mol NaCl * (2 mol HCl / 2 mol NaCl) = 2.57 mol HCl

4. Convert Moles of HCl to Grams

Use the molar mass of HCl (36.46 g/mol) to convert moles to grams:

2.57 mol HCl * (36.46 g HCl / 1 mol HCl) = 93.7 g HCl

Therefore, 93.7 grams of HCl can be prepared from the given amounts of reactants.