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  • Oxidation State of Lead (Pb) in Lead(II) Oxide (Pb3O4): A Step-by-Step Guide
    Here's how to determine the oxidation state of Pb in Pb₃O₄:

    1. Know the oxidation state of oxygen:

    * Oxygen typically has an oxidation state of -2.

    2. Determine the overall charge:

    * Pb₃O₄ is a neutral compound, meaning it has a net charge of 0.

    3. Set up an equation:

    Let 'x' represent the oxidation state of Pb.

    * 3x + 4(-2) = 0

    * 3x - 8 = 0

    4. Solve for x:

    * 3x = 8

    * x = 8/3

    5. Simplify the result:

    The oxidation state of Pb in Pb₃O₄ is +8/3.

    Important Note: The oxidation state of Pb in Pb₃O₄ is a fraction because it represents the average oxidation state of the lead atoms in the compound. Pb₃O₄ is actually a mixed-valence compound, meaning it contains lead atoms in two different oxidation states: +2 and +4.

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