1. Assign Known Oxidation States:
* Hydrogen (H): +1 (almost always)
* Oxygen (O): -2 (except in peroxides and when bonded to fluorine)
2. Set Up the Equation:
Let the oxidation state of iodine be represented by "x." The sum of the oxidation states in a neutral compound must equal zero.
(5 * +1) + x + (6 * -2) = 0
3. Solve for x:
* 5 + x - 12 = 0
* x = +7
Therefore, the oxidation state of iodine in H₅IO₆ is +7.
