1. Determine the Molar Mass of Aluminum Acetate
* Aluminum (Al): 26.98 g/mol
* Acetate (CH₃COO⁻): 59.04 g/mol
* Aluminum Acetate (Al(CH₃COO)₃): 26.98 + (3 * 59.04) = 204.10 g/mol
2. Convert the Mass of Aluminum Acetate to Moles
* Moles = Mass / Molar Mass
* Moles = 33.4 g / 204.10 g/mol = 0.164 mol
3. Convert the Volume of Solution to Liters
* 660 ml = 0.660 L
4. Calculate the Concentration (Molarity)
* Molarity (M) = Moles of Solute / Liters of Solution
* Molarity = 0.164 mol / 0.660 L = 0.248 M
Therefore, the concentration of the aluminum acetate solution is 0.248 M.