Reaction Equation:
2 C₆H₅CH₂OH + 2 Na → 2 C₆H₅CH₂ONa + H₂
Explanation:
1. Sodium Metal (Na): Sodium is a highly reactive alkali metal with a strong tendency to lose an electron and form a cation (Na⁺).
2. Benzyl Alcohol (C₆H₅CH₂OH): This alcohol has a hydroxyl group (-OH) attached to a benzyl group (C₆H₅CH₂-). The hydroxyl group is a weak acid and can be deprotonated by a strong base like sodium.
3. Reaction: The sodium metal reacts with benzyl alcohol, donating an electron to the oxygen atom in the hydroxyl group. This results in the formation of a sodium benzyloxide ion (C₆H₅CH₂ONa) and the release of hydrogen gas (H₂) .
Key Points:
* This reaction is highly exothermic, meaning it releases a significant amount of heat.
* The sodium benzyloxide ion is a strong base and can be used for various organic reactions.
* The hydrogen gas produced is flammable and should be handled with care.
Safety Precautions:
* Sodium metal reacts violently with water, so it should be handled in a dry environment.
* Wear appropriate safety goggles and gloves when working with sodium metal.
Let me know if you have any other questions about organic chemistry!
