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  • Electrolysis of Sodium Hydroxide: Cathode & Anode Products Explained
    Here's a breakdown of what happens during the electrolysis of a sodium hydroxide (NaOH) solution:

    Electrolysis of Sodium Hydroxide Solution

    * Electrolyte: Aqueous solution of NaOH (sodium hydroxide). This solution contains Na+ ions, OH- ions, and water molecules.

    * Electrodes: Usually inert electrodes like platinum or nickel are used to avoid unwanted reactions.

    Reactions at the Electrodes

    * Cathode (Negative Electrode):

    * Primary Reaction: Water molecules gain electrons and are reduced to hydrogen gas and hydroxide ions:

    2H₂O + 2e⁻ → H₂(g) + 2OH⁻

    * Reason: Hydrogen ions (H+) are much less abundant in a basic solution, making the reduction of water more favorable.

    * Anode (Positive Electrode):

    * Primary Reaction: Hydroxide ions lose electrons and are oxidized to oxygen gas and water:

    4OH⁻ → O₂(g) + 2H₂O + 4e⁻

    * Reason: The oxidation of hydroxide ions is more favorable than the oxidation of water.

    Summary of Products

    * Cathode: Hydrogen gas (H₂) is produced.

    * Anode: Oxygen gas (O₂) is produced.

    Important Note: The concentration of NaOH may increase slightly at the cathode due to the formation of additional hydroxide ions. However, the overall composition of the solution will remain largely the same.

    Let me know if you would like a more detailed explanation of the electrochemical principles behind this process!

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