1. Write the unbalanced equation:
NaI (aq) + AgNO₃ (aq) → AgI (s) + NaNO₃ (aq)
2. Identify the products:
* Silver iodide (AgI): This is a yellow precipitate that forms.
* Sodium nitrate (NaNO₃): This remains in solution.
3. Balance the equation:
Notice that the equation is already balanced. There is one silver atom, one iodine atom, one sodium atom, and one nitrate ion on each side of the equation.
Balanced Equation:
NaI (aq) + AgNO₃ (aq) → AgI (s) + NaNO₃ (aq)
Net Ionic Equation:
To get the net ionic equation, we remove the spectator ions (ions that appear on both sides of the equation):
Ag⁺ (aq) + I⁻ (aq) → AgI (s)
Summary:
The reaction between aqueous sodium iodide and aqueous silver nitrate results in the formation of a yellow precipitate of silver iodide (AgI). The balanced equation is:
NaI (aq) + AgNO₃ (aq) → AgI (s) + NaNO₃ (aq)
