Here's how to determine the complete net ionic equation for the reaction between copper sulfate (CuSO₄) and lead nitrate (Pb(NO₃)₂):

1. Write the balanced molecular equation:

CuSO₄(aq) + Pb(NO₃)₂(aq) → Cu(NO₃)₂(aq) + PbSO₄(s)

2. Write the complete ionic equation:

This involves breaking down all soluble ionic compounds into their respective ions:

Cu²⁺(aq) + SO₄²⁻(aq) + Pb²⁺(aq) + 2NO₃⁻(aq) → Cu²⁺(aq) + 2NO₃⁻(aq) + PbSO₄(s)

3. Identify the spectator ions:

These are ions that appear on both sides of the equation and don't participate in the reaction. In this case, the spectator ions are Cu²⁺(aq) and 2NO₃⁻(aq).

4. Write the net ionic equation:

This is the equation that shows only the ions directly involved in the reaction, excluding the spectator ions:

Pb²⁺(aq) + SO₄²⁻(aq) → PbSO₄(s)

Therefore, the complete net ionic equation for the reaction of copper sulfate and lead nitrate is Pb²⁺(aq) + SO₄²⁻(aq) → PbSO₄(s).