1. Write the balanced chemical equation:

The decomposition of boric acid (BOH3) into boric oxide (B2O3) and water (H2O) is represented by the following equation:

2 BOH3 → B2O3 + 3 H2O

2. Calculate the molar mass of BOH3 and B2O3:

* Molar mass of BOH3 = 10.81 (B) + 3 * (1.01 + 16.00) = 61.84 g/mol

* Molar mass of B2O3 = 2 * 10.81 (B) + 3 * 16.00 (O) = 69.62 g/mol

3. Convert the mass of BOH3 to moles:

* Moles of BOH3 = 10 g / 61.84 g/mol = 0.1617 mol

4. Use the mole ratio from the balanced equation to find moles of B2O3:

* From the balanced equation, 2 moles of BOH3 produce 1 mole of B2O3.

* Moles of B2O3 = (0.1617 mol BOH3) * (1 mol B2O3 / 2 mol BOH3) = 0.08085 mol B2O3

5. Convert moles of B2O3 to grams:

* Mass of B2O3 = 0.08085 mol * 69.62 g/mol = 5.63 g

Therefore, 5.63 g of boric oxide (B2O3) is formed from the decomposition of 10 g of boric acid (BOH3).