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  • Solubility in CBr4 and Water: A Polarity-Based Analysis
    Here's how to determine solubility in CBr4 and water:

    Understanding Solubility

    * "Like dissolves like": This principle states that substances with similar polarities are more likely to dissolve in each other.

    * Polarity: Polar molecules have uneven distributions of electron density, creating partial positive and negative charges. Nonpolar molecules have a relatively even distribution of electron density.

    Analyzing the Compounds

    * CBr4 (Carbon Tetrabromide): CBr4 is a nonpolar molecule due to the symmetrical arrangement of the bromine atoms around the central carbon.

    * Water (H2O): Water is a highly polar molecule due to the bent shape and the electronegative oxygen atom.

    Let's analyze each option:

    A. NaCl (Sodium Chloride): Ionic compound, highly polar, will dissolve in water (due to strong ion-dipole interactions). It will not dissolve in CBr4.

    B. HCl (Hydrogen Chloride): Polar molecule due to the electronegativity difference between hydrogen and chlorine. It will be slightly soluble in water and even less soluble in CBr4.

    C. CH3OH (Methanol): Polar molecule due to the presence of a hydroxyl group (-OH). It will be soluble in water (hydrogen bonding) and slightly soluble in CBr4.

    D. CH4 (Methane): Nonpolar molecule. It will be more soluble in CBr4 (due to similar nonpolar interactions) and practically insoluble in water.

    E. C2H6 (Ethane): Nonpolar molecule. It will be more soluble in CBr4 (due to similar nonpolar interactions) and practically insoluble in water.

    Conclusion

    * Most soluble in CBr4: CH4 and C2H6 (due to similar nonpolar character)

    * Most soluble in water: NaCl (due to strong ion-dipole interactions)

    Important Note: Solubility is a complex phenomenon and can be affected by various factors (temperature, pressure, etc.). The above analysis provides a general understanding of the solubility trends based on polarity.

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