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  • Balancing Chemical Equations: Oxygen in the Combustion of Propanol (C3H7OH)
    Here's how to balance the equation for the complete combustion of one mole of C3H7OH (propanol):

    Unbalanced Equation:

    C3H7OH + O2 → CO2 + H2O

    Balancing the Equation:

    1. Carbon (C): There are 3 carbon atoms on the left side and 1 on the right. Multiply CO2 by 3:

    C3H7OH + O2 → 3CO2 + H2O

    2. Hydrogen (H): There are 8 hydrogen atoms on the left side and 2 on the right. Multiply H2O by 4:

    C3H7OH + O2 → 3CO2 + 4H2O

    3. Oxygen (O): There are 3 oxygen atoms on the left side and 10 on the right. Multiply O2 by 9/2:

    C3H7OH + 9/2 O2 → 3CO2 + 4H2O

    4. Whole Number Coefficients: Since we usually use whole number coefficients, multiply the entire equation by 2 to get rid of the fraction:

    2C3H7OH + 9O2 → 6CO2 + 8H2O

    Answer: The coefficient for oxygen in the balanced equation is 9.

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