1. Convert grams to moles:
* Find the molar mass of FeCl₂:
* Fe: 55.845 g/mol
* Cl: 35.453 g/mol
* FeCl₂: 55.845 + (2 * 35.453) = 126.751 g/mol
* Calculate moles of FeCl₂:
* moles = mass / molar mass
* moles = 200 g / 126.751 g/mol
* moles ≈ 1.58 mol
2. Convert mL to Liters:
* 450 mL = 0.45 L
3. Calculate Concentration (Molarity):
* Molarity (M) = moles of solute / liters of solution
* M = 1.58 mol / 0.45 L
* M ≈ 3.51 M
Therefore, the concentration of the iron II chloride solution is approximately 3.51 M.
