1. Find the molar mass of silver nitrate (AgNO₃):
* Ag: 107.87 g/mol
* N: 14.01 g/mol
* O: 16.00 g/mol (x3 = 48.00 g/mol)
Total molar mass = 107.87 + 14.01 + 48.00 = 169.88 g/mol
2. Convert grams of silver nitrate to moles:
* Moles = (mass in grams) / (molar mass)
* Moles = 7.25 g / 169.88 g/mol = 0.0427 mol
3. Convert milliliters of solution to liters:
* Liters = (milliliters) / 1000
* Liters = 100 mL / 1000 = 0.1 L
4. Calculate the molar concentration (molarity):
* Molarity (M) = (moles of solute) / (liters of solution)
* Molarity = 0.0427 mol / 0.1 L = 0.427 M
Therefore, the molar concentration of the silver nitrate solution is 0.427 M.
