1. Find the molar mass of BaCrO₄:
* Ba (Barium): 137.33 g/mol
* Cr (Chromium): 52.00 g/mol
* O (Oxygen): 16.00 g/mol (x 4 = 64.00 g/mol)
Total molar mass of BaCrO₄ = 137.33 + 52.00 + 64.00 = 253.33 g/mol
2. Calculate the mass percentage of chromium:
(Mass of chromium / Molar mass of BaCrO₄) x 100%
(52.00 g/mol / 253.33 g/mol) x 100% = 20.53%
Therefore, the percent composition of chromium in BaCrO₄ is 20.53%.
