1. Write the Balanced Chemical Equation:

4 Na + O₂ → 2 Na₂O

2. Determine the Molar Mass of Sodium (Na) and Sodium Oxide (Na₂O):

* Na: 22.99 g/mol

* Na₂O: (22.99 g/mol * 2) + 16.00 g/mol = 61.98 g/mol

3. Calculate the Moles of Sodium:

* Moles of Na = mass of Na / molar mass of Na

* Moles of Na = 46 g / 22.99 g/mol = 2 moles

4. Use the Mole Ratio from the Balanced Equation:

* The balanced equation shows that 4 moles of Na react to form 2 moles of Na₂O.

5. Calculate the Moles of Sodium Oxide:

* Moles of Na₂O = (2 moles Na) * (2 moles Na₂O / 4 moles Na) = 1 mole Na₂O

6. Calculate the Mass of Sodium Oxide:

* Mass of Na₂O = moles of Na₂O * molar mass of Na₂O

* Mass of Na₂O = 1 mole * 61.98 g/mol = 61.98 g

Answer: If 46 grams of sodium are used in the reaction, 61.98 grams of sodium oxide will be formed.