CH₃CH₂COOH + CH₃CH₂NH₂ ⇌ CH₃CH₂COO⁻ + CH₃CH₂NH₃⁺
Explanation:
* Propanoic acid (CH₃CH₂COOH) is a weak acid.
* Ethylamine (CH₃CH₂NH₂) is a weak base.
* CH₃CH₂COO⁻ is the propanoate anion, the conjugate base of propanoic acid.
* CH₃CH₂NH₃⁺ is the ethylammonium cation, the conjugate acid of ethylamine.
The reaction is an equilibrium reaction. The direction of the equilibrium depends on the relative strengths of the acid and base. In this case, propanoic acid is a slightly stronger acid than ethylamine is a base, so the equilibrium lies slightly to the right, favoring the formation of the salt.
The salt formed is ethylammonium propanoate.
