1. Convert grams of sulfur to moles:

* Find the molar mass of sulfur (S): 32.06 g/mol

* Divide the mass of sulfur by its molar mass: 48.0 g / 32.06 g/mol = 1.50 mol S

2. Use the mole ratio from the balanced equation:

* The balanced equation tells us that 2 moles of Fe react with 3 moles of S.

* Set up a proportion to find the moles of Fe needed: (2 mol Fe / 3 mol S) = (x mol Fe / 1.50 mol S)

* Solve for x: x = 1.00 mol Fe

3. Convert moles of iron to grams:

* Find the molar mass of iron (Fe): 55.845 g/mol

* Multiply the moles of Fe by its molar mass: 1.00 mol Fe * 55.845 g/mol = 55.8 g Fe

Therefore, 55.8 grams of iron are required to react with 48.0 grams of sulfur.