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  • Ionic Compound Formula: S²⁻ and Pb⁴⁺ - Step-by-Step Calculation
    Here's how to determine the formula for the ionic compound formed between S²⁻ (sulfide ion) and Pb⁴⁺ (lead(IV) ion):

    1. Charge Balance:

    * The sulfide ion (S²⁻) has a -2 charge.

    * The lead(IV) ion (Pb⁴⁺) has a +4 charge.

    To achieve a neutral compound, we need to balance these charges.

    2. Finding the Ratio:

    * The least common multiple of 2 and 4 is 4.

    * To get a total charge of +4, we need two sulfide ions (2 x -2 = -4).

    * To get a total charge of -4, we need one lead(IV) ion (+4).

    3. Formula:

    Therefore, the formula for the ionic compound is PbS₂.

    Important Note: This compound is called lead(IV) sulfide.

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