1. Calculate the molar mass of Na3N:

* Na (sodium) has a molar mass of 22.99 g/mol

* N (nitrogen) has a molar mass of 14.01 g/mol

* Molar mass of Na3N = (3 * 22.99 g/mol) + (1 * 14.01 g/mol) = 82.97 g/mol

2. Calculate the moles of Na3N:

* Moles = mass / molar mass

* Moles of Na3N = 100.0 g / 82.97 g/mol = 1.207 moles

3. Use the mole ratio from the balanced equation to find moles of Na and N2:

* From the balanced equation: 2 moles Na3N → 6 moles Na + 1 mole N2

* Moles of Na = (1.207 moles Na3N) * (6 moles Na / 2 moles Na3N) = 3.621 moles Na

* Moles of N2 = (1.207 moles Na3N) * (1 mole N2 / 2 moles Na3N) = 0.6035 moles N2

4. Calculate the mass of Na and N2 formed:

* Mass of Na = moles of Na * molar mass of Na

* Mass of Na = 3.621 moles * 22.99 g/mol = 83.3 g

* Mass of N2 = moles of N2 * molar mass of N2

* Mass of N2 = 0.6035 moles * 28.02 g/mol = 16.9 g

Therefore:

* 83.3 grams of sodium (Na) are formed.

* 16.9 grams of nitrogen (N2) are formed.