1. Calculate the moles of HCl:
* Moles of HCl = Molarity × Volume (in liters)
* Moles of HCl = 2.5 M × 0.003 L = 0.0075 moles
2. Calculate the new molarity after dilution:
* New Molarity = Moles of HCl / New Volume (in liters)
* New Molarity = 0.0075 moles / 0.1 L = 0.075 M
3. Calculate the pH:
* pH = -log[H+]
* pH = -log(0.075) ≈ 1.12
Therefore, the pH of the diluted HCl solution is approximately 1.12.
