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  • Oxygen Production from Potassium Hydroxide and Water: A Stoichiometric Calculation
    Here's how to solve this problem:

    1. Balanced Chemical Equation:

    The balanced chemical equation for the reaction is:

    4KOH + 2H₂O → 4KOH + O₂

    2. Mole Ratio:

    The balanced equation shows that 2 moles of water (H₂O) produce 1 mole of oxygen (O₂).

    3. Moles of Oxygen:

    Since you have 6.21 moles of KOH, and the ratio of KOH to O₂ is 4:1, you'll produce:

    * 6.21 moles KOH * (1 mole O₂ / 4 moles KOH) = 1.5525 moles O₂

    4. Grams of Oxygen:

    To convert moles of oxygen to grams, use the molar mass of oxygen:

    * 1.5525 moles O₂ * (32.00 g O₂ / 1 mole O₂) = 49.68 g O₂

    Therefore, 49.68 grams of oxygen are formed when 6.21 moles of KOH react.

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