The balanced equation for the reaction between sodium phosphate (Na₃PO₄) and lead(II) chloride (PbCl₂) is:

2 Na₃PO₄ (aq) + 3 PbCl₂ (aq) → 6 NaCl (aq) + Pb₃(PO₄)₂ (s)

Here's how to balance the equation:

1. Identify the reactants and products:

- Reactants: Sodium phosphate (Na₃PO₄) and lead(II) chloride (PbCl₂)

- Products: Sodium chloride (NaCl) and lead(II) phosphate (Pb₃(PO₄)₂)

2. Write the unbalanced equation:

Na₃PO₄ + PbCl₂ → NaCl + Pb₃(PO₄)₂

3. Balance the lead (Pb) atoms:

2 Na₃PO₄ + 3 PbCl₂ → NaCl + Pb₃(PO₄)₂

4. Balance the phosphate (PO₄) groups:

2 Na₃PO₄ + 3 PbCl₂ → NaCl + Pb₃(PO₄)₂ (already balanced)

5. Balance the sodium (Na) atoms:

2 Na₃PO₄ + 3 PbCl₂ → 6 NaCl + Pb₃(PO₄)₂

6. Balance the chlorine (Cl) atoms:

2 Na₃PO₄ + 3 PbCl₂ → 6 NaCl + Pb₃(PO₄)₂ (already balanced)

Now the equation is balanced with 2 sodium phosphate molecules, 3 lead(II) chloride molecules, 6 sodium chloride molecules, and 1 lead(II) phosphate molecule.