The reaction of 2-naphthol with sodium hydroxide is a simple acid-base reaction. 2-naphthol is a weak acid, and sodium hydroxide is a strong base. The reaction produces the 2-naphthoxide anion and water:

2-naphthol + NaOH → 2-naphthoxide anion + H₂O

Here's the more detailed chemical equation:

C₁₀H₇OH + NaOH → C₁₀H₇O⁻ + Na⁺ + H₂O

Where:

* C₁₀H₇OH represents 2-naphthol

* NaOH represents sodium hydroxide

* C₁₀H₇O⁻ represents the 2-naphthoxide anion

* Na⁺ represents the sodium cation

* H₂O represents water

Important Note: This reaction is an equilibrium reaction. The 2-naphthoxide anion can react with water to regenerate 2-naphthol and hydroxide ions. However, because sodium hydroxide is a strong base, the equilibrium will favor the formation of the 2-naphthoxide anion.