Here's the balanced chemical equation:
F₂(g) + 2KI(s) → 2KF(s) + I₂(s)
Explanation:
* Fluorine (F₂) is a highly reactive halogen, meaning it readily accepts electrons.
* Potassium iodide (KI) is an ionic compound, with potassium (K⁺) and iodide (I⁻) ions.
* Fluorine is more electronegative than iodine, so it will displace iodide from the compound.
* The reaction results in the formation of potassium fluoride (KF), another ionic compound, and elemental iodine (I₂).
Key points:
* The reaction is highly exothermic, meaning it releases a significant amount of heat.
* The reaction is vigorous, meaning it proceeds rapidly.
* This reaction is a classic example of a halogen displacement reaction.
* Due to the extreme reactivity of fluorine, it is important to handle this reaction with extreme caution and only in a well-ventilated laboratory setting with appropriate safety equipment.
Note: This reaction is not typically used in everyday applications. It's primarily used for demonstrating the reactivity of fluorine and the concept of halogen displacement.