Here's how to calculate the moles of ammonium hydroxide (NH₄OH) present in 0.475 g:

1. Find the molar mass of NH₄OH:

* N: 14.01 g/mol

* H: 1.01 g/mol (there are 5 hydrogen atoms)

* O: 16.00 g/mol

Total molar mass = 14.01 + (1.01 x 5) + 16.00 = 35.06 g/mol

2. Use the formula: moles = mass / molar mass

* moles = 0.475 g / 35.06 g/mol

* moles ≈ 0.0136 mol

Therefore, approximately 0.0136 moles of ammonium hydroxide are present in 0.475 g.