The reaction between fluorine (F₂) and potassium bromide (KBr) is a single displacement reaction where fluorine, being a more reactive halogen, displaces bromide ions from potassium bromide, forming potassium fluoride (KF) and bromine (Br₂).

The balanced chemical equation is:

F₂(g) + 2KBr(s) → 2KF(s) + Br₂(l)

Explanation:

* Fluorine (F₂) is a highly reactive element and is a strong oxidizing agent.

* Potassium bromide (KBr) is a white crystalline solid.

* Potassium fluoride (KF) is a white crystalline solid.

* Bromine (Br₂) is a reddish-brown liquid.

Observations:

* The reaction is exothermic and produces heat.

* Bromine gas is released, which has a distinctive reddish-brown color and a pungent odor.

Important Note: This reaction is highly exothermic and should be carried out with extreme caution in a fume hood due to the release of toxic bromine gas.