1. Write the balanced chemical equation:

N₂ + 3H₂ → 2NH₃

This tells us that 1 mole of nitrogen gas (N₂) reacts with 3 moles of hydrogen gas (H₂) to produce 2 moles of ammonia (NH₃).

2. Calculate the moles of each reactant:

* Nitrogen (N₂):

* Molar mass of N₂ = 28.0 g/mol

* Moles of N₂ = (28.0 g) / (28.0 g/mol) = 1.0 mol

* Hydrogen (H₂):

* Molar mass of H₂ = 2.0 g/mol

* Moles of H₂ = (6.0 g) / (2.0 g/mol) = 3.0 mol

3. Determine the limiting reactant:

The balanced equation shows that 1 mole of N₂ reacts with 3 moles of H₂. We have exactly the right amount of each reactant, so neither is limiting.

4. Calculate the moles of ammonia produced:

From the balanced equation, 1 mole of N₂ produces 2 moles of NH₃. Since we have 1 mole of N₂, we will produce 2 moles of NH₃.

5. Calculate the mass of ammonia produced:

* Molar mass of NH₃ = 17.0 g/mol

* Mass of NH₃ = (2.0 mol) * (17.0 g/mol) = 34.0 g

Therefore, the mass of ammonia produced is 34.0 g.