Here's how to determine the number of bonds in a cyanogen bromide (BrCN) molecule:

* Lewis Structure:

* Carbon (C) has 4 valence electrons.

* Nitrogen (N) has 5 valence electrons.

* Bromine (Br) has 7 valence electrons.

* Bonding:

* Carbon forms a triple bond with nitrogen (C≡N).

* Carbon forms a single bond with bromine (C-Br).

Total Bonds: 1 triple bond + 1 single bond = 4 bonds

Therefore, there are 4 bonds in a cyanogen bromide (BrCN) molecule.