* Solubility is temperature dependent: The amount of a substance that can dissolve in a given amount of solvent (water in this case) changes with temperature. Solubility generally increases as temperature increases. You need to know the temperature of the water.
* Copper sulfate forms hydrates: Copper sulfate exists in different forms, including anhydrous CuSO4 and various hydrated forms like CuSO4·5H2O. The solubility of these different forms varies. You need to know the specific form of copper sulfate you're dealing with.
To figure this out, you'll need:
1. The temperature of the water: Look up the solubility of copper sulfate (in the form you're using) at that temperature. Solubility is usually expressed in grams of solute per 100 grams of solvent.
2. The density of water: You'll need this to convert 1750 mL of water into grams.
Here's how you can then solve the problem:
1. Find the solubility of CuSO4: Use a solubility table or online resource to find the solubility of CuSO4 (in the appropriate form) at the given temperature.
2. Calculate the maximum mass of CuSO4 that can dissolve: Multiply the solubility (grams CuSO4 per 100 grams of water) by the mass of the water (calculated from the volume and density).
3. Compare the maximum mass to the given mass: If the maximum mass is greater than or equal to 4.6 g, then the water can dissolve it. If the maximum mass is less than 4.6 g, then the water cannot dissolve all of the CuSO4.
Example (assuming 25°C and anhydrous CuSO4):
* Solubility of anhydrous CuSO4 at 25°C: ~20 g/100 g water
* Density of water at 25°C: ~1 g/mL
* Mass of water: 1750 mL * 1 g/mL = 1750 g
* Maximum CuSO4 that can dissolve: (20 g CuSO4 / 100 g water) * 1750 g water = 350 g CuSO4
In this example, 1750 mL of water at 25°C could dissolve far more than 4.6 g of anhydrous CuSO4.
