CaCl₂(aq) + Na₂C₂O₄(aq) → CaC₂O₄(s) + 2NaCl(aq)
Here's a breakdown of the reaction:
* Reactants:
* Calcium chloride (CaCl₂): A soluble ionic compound.
* Sodium oxalate (Na₂C₂O₄): A soluble ionic compound.
* Products:
* Calcium oxalate (CaC₂O₄): An insoluble ionic compound that precipitates out of solution as a solid.
* Sodium chloride (NaCl): A soluble ionic compound that remains in solution.
Explanation:
This reaction is a double displacement reaction, where the cations and anions of the two reactants switch places.
* Calcium ions (Ca²⁺) from calcium chloride combine with oxalate ions (C₂O₄²⁻) from sodium oxalate to form calcium oxalate (CaC₂O₄), which is insoluble in water and precipitates out as a solid.
* Sodium ions (Na⁺) from sodium oxalate combine with chloride ions (Cl⁻) from calcium chloride to form sodium chloride (NaCl), which remains dissolved in solution.
The balanced equation ensures that the number of atoms of each element is the same on both sides of the equation. In this case, we have:
* 1 Calcium atom (Ca)
* 2 Chlorine atoms (Cl)
* 2 Sodium atoms (Na)
* 2 Carbon atoms (C)
* 4 Oxygen atoms (O)
on both the reactant and product sides.
