Tolbutamide, a sulfonylurea drug, undergoes hydrolysis in the presence of a strong base like sodium hydroxide (NaOH). The reaction results in the formation of toluenesulfonamide and N-methyl-N'-[2-(methylsulfonyl)phenyl]urea:

Reaction Equation:

```

Tolbutamide + NaOH → Toluenesulfonamide + N-methyl-N'-[2-(methylsulfonyl)phenyl]urea + Na+ + H2O

```

Detailed Breakdown:

1. Hydrolysis: The hydroxide ion (OH-) from NaOH attacks the carbonyl carbon of the sulfonylurea group in tolbutamide.

2. Bond Cleavage: The bond between the carbonyl carbon and the nitrogen atom of the urea group breaks.

3. Formation of Products:

* One product is toluenesulfonamide, formed by the removal of the urea group from tolbutamide.

* The other product is N-methyl-N'-[2-(methylsulfonyl)phenyl]urea, formed by the addition of a hydroxide ion to the carbonyl carbon.

Important Note: This reaction is typically carried out under basic conditions to promote hydrolysis. The reaction may also be influenced by factors like temperature and reaction time.

Note: The exact mechanism of hydrolysis can be complex, and the above explanation provides a simplified representation.