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  • Calculating Ferrous Ammonium Sulfate Normality: A Step-by-Step Guide
    Here's how to find the normality of a ferrous ammonium sulfate solution:

    Understanding Normality

    * Normality (N) is a measure of concentration that refers to the number of gram equivalents of a solute dissolved per liter of solution.

    * Gram Equivalent Weight (GEW) is the molecular weight of a substance divided by the number of equivalents it produces in a reaction.

    Steps to Determine Normality

    1. Write the Balanced Chemical Equation: This is crucial to determine the number of equivalents the ferrous ammonium sulfate will produce in a specific reaction. For example, let's assume you're using it as a reducing agent in a redox reaction where Fe²⁺ is oxidized to Fe³⁺:

    Fe²⁺ + e⁻ → Fe³⁺

    2. Calculate the Molecular Weight (MW) of Ferrous Ammonium Sulfate (FeSO₄(NH₄)₂SO₄·6H₂O):

    * Fe: 55.845 g/mol

    * S: 32.065 g/mol

    * O: 15.999 g/mol

    * N: 14.007 g/mol

    * H: 1.008 g/mol

    * MW = (55.845 + 32.065 + 15.999*4 + 14.007*2 + 1.008*8 + 15.999*6) = 392.14 g/mol

    3. Determine the Number of Equivalents: In the reaction above, one mole of ferrous ammonium sulfate (FeSO₄(NH₄)₂SO₄·6H₂O) produces one mole of Fe²⁺, which releases one electron (e⁻). Therefore, one mole of ferrous ammonium sulfate is equivalent to one equivalent.

    4. Calculate the Gram Equivalent Weight (GEW):

    * GEW = MW / Number of Equivalents = 392.14 g/mol / 1 = 392.14 g/equivalent

    5. Determine the Mass of Ferrous Ammonium Sulfate: Weigh out the exact mass of ferrous ammonium sulfate you are using for your solution.

    6. Calculate the Normality:

    * Normality (N) = (Mass of Solute (g) / GEW (g/equivalent)) / Volume of Solution (L)

    Example:

    * You dissolve 10.0 g of ferrous ammonium sulfate in 250 mL of water.

    * Step 1: You have the balanced equation from earlier.

    * Step 2: You calculated the MW to be 392.14 g/mol.

    * Step 3: You know one mole produces one equivalent.

    * Step 4: You calculated the GEW to be 392.14 g/equivalent.

    * Step 5: You have 10.0 g of ferrous ammonium sulfate.

    * Step 6:

    * N = (10.0 g / 392.14 g/equivalent) / (0.250 L)

    * N ≈ 0.102 N

    Important Notes:

    * Hydrated Salt: Be sure to use the molecular weight of the hydrated form of ferrous ammonium sulfate (FeSO₄(NH₄)₂SO₄·6H₂O) if you are using the hydrated salt.

    * Reaction-Specific: Normality is reaction-specific. The number of equivalents will vary depending on the reaction where the ferrous ammonium sulfate is used.

    * Purity: If your ferrous ammonium sulfate is not 100% pure, you will need to adjust your calculations accordingly.

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