1. Find the molar mass of LiCl:
* Li (Lithium) has a molar mass of 6.941 g/mol
* Cl (Chlorine) has a molar mass of 35.453 g/mol
* Molar mass of LiCl = 6.941 g/mol + 35.453 g/mol = 42.394 g/mol
2. Calculate the number of moles of LiCl:
* Moles = Mass / Molar Mass
* Moles = 127.17 g / 42.394 g/mol = 3.00 mol
3. Use Avogadro's number to find the number of molecules:
* Avogadro's number = 6.022 x 10^23 molecules/mol
* Number of molecules = Moles * Avogadro's number
* Number of molecules = 3.00 mol * 6.022 x 10^23 molecules/mol = 1.81 x 10^24 molecules
Therefore, there are approximately 1.81 x 10^24 molecules of LiCl in a 127.17 g sample.
