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  • Lithium and Bromine Bonding: Understanding Ionic Bond Formation
    Lithium (Li) has one valence electron, while Bromine (Br) has seven valence electrons. Here's how they form a chemical bond:

    * Lithium wants to lose its one valence electron to achieve a stable, full outer shell like Helium (2 electrons). This makes it positively charged (+1).

    * Bromine wants to gain one electron to achieve a stable, full outer shell like Krypton (8 electrons). This makes it negatively charged (-1).

    The Result:

    The strong electrostatic attraction between the positively charged lithium ion (Li+) and the negatively charged bromide ion (Br-) forms an ionic bond. This results in the formation of Lithium Bromide (LiBr), a stable ionic compound.

    Visual Representation:

    * Lithium: [He] 2s¹ --> [He] (loses electron) --> Li+

    * Bromine: [Ar] 4s² 3d¹⁰ 4p⁵ --> [Ar] 4s² 3d¹⁰ 4p⁶ (gains electron) --> Br-

    In essence, Lithium donates its electron to Bromine, forming a stable ionic compound with a 1:1 ratio.

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