Here's how to write the ionic equation for the reaction between barium chloride (BaCl₂) and copper sulfate (CuSO₄):

1. Write the Balanced Molecular Equation:

BaCl₂(aq) + CuSO₄(aq) → BaSO₄(s) + CuCl₂(aq)

2. Identify the Spectator Ions:

* Spectator ions are ions that appear on both sides of the equation and do not participate in the reaction.

* In this case, the spectator ions are Ba²⁺(aq) and Cl⁻(aq).

3. Write the Complete Ionic Equation:

Ba²⁺(aq) + 2Cl⁻(aq) + Cu²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s) + Cu²⁺(aq) + 2Cl⁻(aq)

4. Cancel Out the Spectator Ions:

Ba²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s)

This is the net ionic equation for the reaction.

Explanation:

* The reaction forms a precipitate of barium sulfate (BaSO₄), which is why it's shown in the solid state (s).

* The copper(II) ions (Cu²⁺) and chloride ions (Cl⁻) remain in solution as they are spectator ions.

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