1. Find the molar mass of KMnO4:

* K (potassium) = 39.0983 g/mol

* Mn (manganese) = 54.9380 g/mol

* O (oxygen) = 15.9994 g/mol * 4 = 63.9976 g/mol

Total molar mass of KMnO4 = 39.0983 + 54.9380 + 63.9976 = 158.0339 g/mol

2. Calculate the moles of KMnO4:

* Moles = mass / molar mass

* Moles of KMnO4 = 16.1201 g / 158.0339 g/mol = 0.1020 mol

3. Determine the moles of Mn atoms:

* There is one Mn atom per molecule of KMnO4.

* Therefore, the moles of Mn atoms are equal to the moles of KMnO4.

Answer: There are 0.1020 moles of Mn atoms in 16.1201 grams of KMnO4.