1. Convert mass to moles:
* Calcium (Ca): 3.609 g Ca / 40.08 g/mol Ca = 0.0900 mol Ca
* Chlorine (Cl): 6.384 g Cl / 35.45 g/mol Cl = 0.1800 mol Cl
2. Find the mole ratio:
* Divide the number of moles of each element by the smallest number of moles:
* Ca: 0.0900 mol / 0.0900 mol = 1
* Cl: 0.1800 mol / 0.0900 mol = 2
3. Write the empirical formula:
* The mole ratio indicates that the empirical formula is CaCl₂.
Therefore, the empirical formula of the compound is CaCl₂.