1. Look up the electronegativity values:
* Sodium (Na): 0.93
* Bromine (Br): 2.96
2. Calculate the difference:
Electronegativity difference = 2.96 - 0.93 = 2.03
Therefore, the electronegativity difference between sodium and bromine is 2.03.
What does this tell us?
A large electronegativity difference (like this one) indicates that the bond between sodium and bromine is highly ionic. This means that electrons are transferred from the sodium atom (less electronegative) to the bromine atom (more electronegative), resulting in the formation of Na+ and Br- ions.
