1. Calculate the molar mass of HNO3:
* H: 1.01 g/mol
* N: 14.01 g/mol
* O: 16.00 g/mol (x 3)
* Total molar mass: 1.01 + 14.01 + (16.00 * 3) = 63.02 g/mol
2. Calculate the number of moles of HNO3:
* moles = mass / molar mass
* moles = 60g / 63.02 g/mol
* moles ≈ 0.952 mol
3. Calculate the number of molecules of HNO3:
* molecules = moles * Avogadro's number (6.022 x 10^23 molecules/mol)
* molecules ≈ 0.952 mol * 6.022 x 10^23 molecules/mol
* molecules ≈ 5.73 x 10^23 molecules
4. Calculate the total number of atoms:
* Each HNO3 molecule contains 5 atoms (1 H + 1 N + 3 O)
* Total atoms = molecules * atoms per molecule
* Total atoms ≈ 5.73 x 10^23 molecules * 5 atoms/molecule
* Total atoms ≈ 2.87 x 10^24 atoms
Therefore, approximately 2.87 x 10^24 atoms are required to prepare 60g of HNO3.
