Here's how to determine the net ionic equation for the reaction of sodium acetate (NaCH₃COO) and hydrochloric acid (HCl):

1. Write the balanced molecular equation:

NaCH₃COO(aq) + HCl(aq) → CH₃COOH(aq) + NaCl(aq)

2. Write the complete ionic equation:

Na⁺(aq) + CH₃COO⁻(aq) + H⁺(aq) + Cl⁻(aq) → CH₃COOH(aq) + Na⁺(aq) + Cl⁻(aq)

3. Identify the spectator ions:

Spectator ions are ions that appear on both sides of the equation and do not participate in the reaction. In this case, Na⁺ and Cl⁻ are spectator ions.

4. Write the net ionic equation:

The net ionic equation includes only the species that directly participate in the reaction:

H⁺(aq) + CH₃COO⁻(aq) → CH₃COOH(aq)

This equation represents the formation of acetic acid (CH₃COOH) from the reaction of hydrogen ions (H⁺) and acetate ions (CH₃COO⁻).