1. Write the complete ionic equation:
* NaCl(aq) → Na⁺(aq) + Cl⁻(aq)
* AgC₂H₃O₂(aq) → Ag⁺(aq) + C₂H₃O₂⁻(aq)
* Na⁺(aq) + C₂H₃O₂⁻(aq) → NaC₂H₃O₂(aq)
* Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
2. Identify spectator ions:
* Na⁺(aq) and C₂H₃O₂⁻(aq) are spectator ions because they appear on both sides of the equation unchanged.
3. Write the net ionic equation by removing spectator ions:
Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
Therefore, the net ionic equation for the reaction is:
Ag⁺(aq) + Cl⁻(aq) → AgCl(s)