1. Find the Molar Mass of Aluminum Chloride:
* Aluminum (Al) has a molar mass of 26.98 g/mol.
* Chlorine (Cl) has a molar mass of 35.45 g/mol.
* Since there are three chlorine atoms in AlCl₃, the total mass of chlorine is 3 * 35.45 g/mol = 106.35 g/mol.
* The molar mass of AlCl₃ is 26.98 g/mol + 106.35 g/mol = 133.33 g/mol.
2. Use the Formula:
* Moles (n) = Mass (m) / Molar Mass (M)
3. Calculate the Number of Moles:
* n = 32.5 g / 133.33 g/mol
* n ≈ 0.244 moles
Therefore, there are approximately 0.244 moles of aluminum chloride in 32.5 g.
