Cl₂ (g) + 2 KI (aq) → 2 KCl (aq) + I₂ (s)
Here's a breakdown of the reaction:
* Chlorine gas (Cl₂) is a strong oxidizing agent.
* Potassium iodide (KI) is a solution of potassium ions (K⁺) and iodide ions (I⁻).
* Chlorine displaces iodide ions from the solution.
* Potassium chloride (KCl) is formed, which is soluble in water.
* Iodine (I₂) is formed as a solid precipitate.
The reaction is characterized by the formation of a brown-black precipitate of iodine, which is a distinctive indicator of this reaction.