The balanced equation for the reaction between lithium carbonate (Li₂CO₃) and iron(II) iodide (FeI₂) is:

Li₂CO₃(aq) + FeI₂(aq) → 2LiI(aq) + FeCO₃(s)

Here's a breakdown of the reaction:

* Reactants:

* Lithium carbonate (Li₂CO₃): A white, soluble ionic compound.

* Iron(II) iodide (FeI₂): A yellowish, soluble ionic compound.

* Products:

* Lithium iodide (LiI): A soluble ionic compound.

* Iron(II) carbonate (FeCO₃): An insoluble solid precipitate (that's why it's in the (s) state).

Explanation of Balancing:

* Li: There are 2 Li atoms on the left side and 2 Li atoms on the right side.

* C: There is 1 C atom on both sides.

* O: There are 3 O atoms on both sides.

* Fe: There is 1 Fe atom on both sides.

* I: There are 2 I atoms on both sides.

The equation is now balanced with the same number of each type of atom on both sides of the reaction.