* Copper (Cu) and a concentrated solution of sulfuric acid (H₂SO₄)
Here's how the reaction proceeds:
Reaction:
Cu(s) + 2H₂SO₄(conc.) → CuSO₄(aq) + SO₂(g) + 2H₂O(l)
Explanation:
* Copper reacts with concentrated sulfuric acid.
* The sulfuric acid acts as both an oxidizing agent and an acid.
* Copper is oxidized to copper(II) ions (Cu²⁺), while the sulfuric acid is reduced to sulfur dioxide (SO₂).
* The copper(II) ions then react with sulfate ions (SO₄²⁻) from the sulfuric acid to form copper sulfate (CuSO₄).
Important Notes:
* This reaction is a redox reaction (oxidation-reduction).
* The reaction is carried out in a concentrated solution of sulfuric acid because dilute sulfuric acid will not react with copper.
* This reaction generates sulfur dioxide gas (SO₂), which is a toxic and corrosive gas.
Let me know if you have any other questions!