The reaction between Iron (II) chloride (FeCl₂ ) and sodium phosphate (Na₃PO₄) is a double displacement reaction that produces iron(II) phosphate (Fe₃(PO₄)₂) and sodium chloride (NaCl).

Here's the balanced chemical equation:

3 FeCl₂ (aq) + 2 Na₃PO₄ (aq) → Fe₃(PO₄)₂ (s) + 6 NaCl (aq)

Here's what happens:

* Iron (II) chloride (FeCl₂) and sodium phosphate (Na₃PO₄) are both soluble in water, so they exist as ions in solution.

* Iron (II) ions (Fe²⁺) and phosphate ions (PO₄³⁻) have a strong attraction for each other, forming an insoluble precipitate, iron(II) phosphate (Fe₃(PO₄)₂). This precipitate forms a solid that falls out of solution.

* Sodium ions (Na⁺) and chloride ions (Cl⁻) remain in solution as they are soluble, forming sodium chloride (NaCl).

Observations:

* You would see a cloudy white precipitate forming in the solution as the iron(II) phosphate precipitates out.

* The solution would become less clear due to the precipitate.

Note: This reaction is also an example of a precipitation reaction, where an insoluble solid (precipitate) forms from the reaction of two soluble reactants.